std::log1p
Defined in header <cmath>
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float log1p( float arg ); |
(1) | (since C++11) |
double log1p( double arg ); |
(2) | (since C++11) |
long double log1p( long double arg ); |
(3) | (since C++11) |
double log1p( Integral arg ); |
(4) | (since C++11) |
arg
is close to zero.Parameters
arg | - | value of floating-point or Integral type |
Return value
If no errors occur ln(1+arg) is returned.
If a domain error occurs, an implementation-defined value is returned (NaN where supported)
If a pole error occurs, -HUGE_VAL
, -HUGE_VALF
, or -HUGE_VALL
is returned.
If a range error occurs due to underflow, the correct result (after rounding) is returned.
Error handling
Errors are reported as specified in math_errhandling
Domain error occurs if arg
is less than -1.
Pole error may occur if arg
is -1.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- If the argument is ±0, it is returned unmodified
- If the argument is -1, -∞ is returned and FE_DIVBYZERO is raised.
- If the argument is less than -1, NaN is returned and FE_INVALID is raised.
- If the argument is +∞, +∞ is returned
- If the argument is NaN, NaN is returned
Notes
The functions std::expm1 and std::log1p
are useful for financial calculations, for example, when calculating small daily interest rates: (1+x)n
-1 can be expressed as std::expm1(n * std::log1p(x)). These functions also simplify writing accurate inverse hyperbolic functions.
Example
#include <iostream> #include <cfenv> #include <cmath> #include <cerrno> #include <cstring> #pragma STDC FENV_ACCESS ON int main() { std::cout << "log1p(0) = " << log1p(0) << '\n' << "Interest earned in 2 days on on $100, compounded daily at 1%\n" << " on a 30/360 calendar = " << 100*expm1(2*log1p(0.01/360)) << '\n' << "log(1+1e-16) = " << std::log(1+1e-16) << " log1p(1e-16) = " << std::log1p(1e-16) << '\n'; // special values std::cout << "log1p(-0) = " << std::log1p(-0.0) << '\n' << "log1p(+Inf) = " << std::log1p(INFINITY) << '\n'; // error handling errno=0; std::feclearexcept(FE_ALL_EXCEPT); std::cout << "log1p(-1) = " << std::log1p(-1) << '\n'; if(errno == ERANGE) std::cout << " errno == ERANGE: " << std::strerror(errno) << '\n'; if(std::fetestexcept(FE_DIVBYZERO)) std::cout << " FE_DIVBYZERO raised\n"; }
Possible output:
log1p(0) = 0 Interest earned in 2 days on on $100, compounded daily at 1% on a 30/360 calendar = 0.00555563 log(1+1e-16) = 0 log1p(1e-16) = 1e-16 log1p(-0) = -0 log1p(+Inf) = inf log1p(-1) = -inf errno == ERANGE: Result too large FE_DIVBYZERO raised
See also
computes natural (base e) logarithm (to base e) (ln(x)) (function) | |
computes common (base 10) logarithm (log10(x)) (function) | |
(C++11) |
base 2 logarithm of the given number (log2(x)) (function) |
(C++11) |
returns e raised to the given power, minus one (ex-1) (function) |
C documentation for log1p
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