std::allocator<T>::deallocate
From cppreference.com
void deallocate( T* p, std::size_t n ); |
||
Deallocates the storage referenced by the pointer p
, which must be a pointer obtained by an earlier call to allocate().
The argument n
must be equal to the first argument of the call to allocate() that originally produced p
; otherwise, the behavior is undefined.
Calls ::operator delete(void*) or ::operator delete(void*, std::align_val_t) (since C++17), but it is unspecified when and how it is called.
Parameters
p | - | pointer obtained from allocate()
|
n | - | number of objects earlier passed to allocate()
|
Return value
(none)
See also
allocates uninitialized storage (public member function) | |
[static] |
deallocates storage using the allocator (public static member function of std::allocator_traits<Alloc> ) |