std::allocator<T>::allocate
pointer allocate( size_type n, const void * hint = 0 ); |
(1) | (until C++17) |
T* allocate( std::size_t n, const void * hint); |
(1) | (since C++17) (deprecated) (removed in C++20) |
(2) | ||
T* allocate( std::size_t n ); |
(since C++17) (until C++20) |
|
[[nodiscard]] T* allocate( std::size_t n ); |
(since C++20) | |
Allocates n * sizeof(T) bytes of uninitialized storage by calling ::operator new(std::size_t) or ::operator new(std::size_t, std::align_val_t) (since C++17), but it is unspecified when and how this function is called. The pointer hint
may be used to provide locality of reference: the allocator, if supported by the implementation, will attempt to allocate the new memory block as close as possible to hint
.
Parameters
n | - | the number of objects to allocate storage for |
hint | - | pointer to a nearby memory location |
Return value
Pointer to the first byte of a memory block suitably aligned and sufficient to hold an array of n
objects of type T
.
Exceptions
Throws std::bad_alloc if allocation fails.
Notes
The "unspecified when and how" wording makes it possible to combine or optimize away heap allocations made by the standard library containers, even though such optimizations are disallowed for direct calls to ::operator new
. For example, this is implemented by libc++ ([1] and [2])
See also
[static] |
allocates uninitialized storage using the allocator (public static member function of std::allocator_traits<Alloc> ) |