std::get_if
From cppreference.com
Defined in header <variant>
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(1) | (since C++17) | |
template <std::size_t I, class... Types> constexpr std::add_pointer_t< |
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template <std::size_t I, class... Types> constexpr std::add_pointer_t< |
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(2) | (since C++17) | |
template <class T, class... Types> constexpr std::add_pointer_t<T> get_if(variant<Types...>* pv) |
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template <class T, class... Types> constexpr std::add_pointer_t<const T> get_if(const variant<Types...>* pv) |
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1) Index-based non-throwing accessor: If
pv
is not a null pointer and pv->index() == I, returns a pointer to the value stored in the variant pointed to by pv
. Otherwise, returns a null pointer value. The call is ill-formed if I
is not a valid index in the variant or if T_I
is a (possibly cv-qualified) type void
.2) Type-based non-throwing accessor: Equivalent to (1) with
I
being the zero-based index of T
in Types...
. The call is ill-formed if T
is not a unique element of Types...
or if T_I
is a (possibly cv-qualified) type void
.Parameters
I | - | index to look up |
Type | - | unique type to look up |
pv | - | pointer to a variant |
Return value
Pointer to the value stored in the pointed-to variant or null pointer on error.
Exceptions
1,2)
noexcept specification:
noexcept
Example
Run this code
#include <variant> #include <iostream> int main() { std::variant<int, float> v{12}; if(auto pval = std::get_if<int>(&v)) std::cout << "variant value: " << *pval << '\n'; else std::cout << "failed to get value!" << '\n'; }
Output:
variant value: 12
See also
(C++17) |
reads the value of the variant given the index or the type (if the type is unique), throws on error (function template) |