std::is_sorted_until
Defined in header <algorithm>
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template< class ForwardIt > ForwardIt is_sorted_until( ForwardIt first, ForwardIt last ); |
(1) | (since C++11) |
template< class ExecutionPolicy, class ForwardIt > ForwardIt is_sorted_until( ExecutionPolicy&& policy, ForwardIt first, ForwardIt last ); |
(2) | (since C++17) |
template< class ForwardIt, class Compare > ForwardIt is_sorted_until( ForwardIt first, ForwardIt last, |
(3) | (since C++11) |
template< class ExecutionPolicy, class ForwardIt, class Compare > ForwardIt is_sorted_until( ExecutionPolicy&& policy, ForwardIt first, ForwardIt last, |
(4) | (since C++17) |
Examines the range [first, last)
and finds the largest range beginning at first
in which the elements are sorted in ascending order.
operator<
.comp
.policy
. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueParameters
first, last | - | the range of elements to examine |
policy | - | the execution policy to use. See execution policy for details. |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if the first argument is less than (i.e. is ordered before) the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function object must not modify the objects passed to it. |
Type requirements | ||
-ForwardIt must meet the requirements of ForwardIterator .
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Return value
The upper bound of the largest range beginning at first
in which the elements are sorted in ascending order. That is, the last iterator it
for which range [first, it)
is sorted.
Complexity
linear in the distance between first
and last
Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the three standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
First version |
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template<class ForwardIt> ForwardIt is_sorted_until(ForwardIt first, ForwardIt last) { if (first != last) { ForwardIt next = first; while (++next != last) { if (*next < *first) return next; first = next; } } return last; } |
Second version |
template <class ForwardIt, class Compare> ForwardIt is_sorted_until(ForwardIt first, ForwardIt last, Compare comp) { using namespace std::placeholders; ForwardIt it = std::adjacent_find(first, last, std::bind(comp, _2, _1)); return it == last ? last : std::next(it); } |
Example
#include <iostream> #include <algorithm> #include <iterator> #include <random> int main() { std::random_device rd; std::mt19937 g(rd()); const int N = 6; int nums[N] = {3, 1, 4, 1, 5, 9}; const int min_sorted_size = 4; int sorted_size = 0; do { std::shuffle(nums, nums + N, g); int *sorted_end = std::is_sorted_until(nums, nums + N); sorted_size = std::distance(nums, sorted_end); for (auto i : nums) std::cout << i << ' '; std::cout << " : " << sorted_size << " initial sorted elements\n"; } while (sorted_size < min_sorted_size); }
Possible output:
4 1 9 5 1 3 : 1 initial sorted elements 4 5 9 3 1 1 : 3 initial sorted elements 9 3 1 4 5 1 : 1 initial sorted elements 1 3 5 4 1 9 : 3 initial sorted elements 5 9 1 1 3 4 : 2 initial sorted elements 4 9 1 5 1 3 : 2 initial sorted elements 1 1 4 9 5 3 : 4 initial sorted elements
See also
(C++11) |
checks whether a range is sorted into ascending order (function template) |