std::make_move_iterator
From cppreference.com
Defined in header <iterator>
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template< class Iter > std::move_iterator<Iter> make_move_iterator( const Iter& i ); |
(since C++11) (until C++14) |
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template< class Iter > std::move_iterator<Iter> make_move_iterator( Iter i ); |
(since C++14) (until C++17) |
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template< class Iter > constexpr std::move_iterator<Iter> make_move_iterator( Iter i ); |
(since C++17) | |
make_move_iterator
is a convenience function template that constructs a std::move_iterator for the given iterator i
with the type deduced from the type of the argument.
Parameters
i | - | input iterator to be converted to move iterator |
Return value
A std::move_iterator which can be used to move from the elements accessed through i
Possible implementation
template< class Iter > constexpr std::move_iterator<Iter> make_move_iterator( Iter i ) { return std::move_iterator<Iter>(i); } |
Example
Run this code
#include <iostream> #include <list> #include <vector> #include <string> #include <iterator> int main() { std::list<std::string> s{"one", "two", "three"}; std::vector<std::string> v1(s.begin(), s.end()); // copy std::vector<std::string> v2(std::make_move_iterator(s.begin()), std::make_move_iterator(s.end())); // move std::cout << "v1 now holds: "; for (auto str : v1) std::cout << "\"" << str << "\" "; std::cout << "\nv2 now holds: "; for (auto str : v2) std::cout << "\"" << str << "\" "; std::cout << "\noriginal list now holds: "; for (auto str : s) std::cout << "\"" << str << "\" "; std::cout << '\n'; }
Possible output:
v1 now holds: "one" "two" "three" v2 now holds: "one" "two" "three" original list now holds: "" "" ""
See also
(C++11) |
iterator adaptor which dereferences to an rvalue reference (class template) |
(C++11) |
obtains an rvalue reference (function template) |