std::experimental::filesystem::path::root_name
From cppreference.com
< cpp | experimental | fs | path
path root_name() const; |
(filesystem TS) | |
Returns the root name of the path. If the path does not include root name, returns path().
Parameters
(none)
Return value
The root name of the path.
Exceptions
(none)
Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { std::cout << "Current root name is: " << fs::current_path().root_name() << '\n'; }
Possible output:
Current root name is: "C:"
See also
returns the root directory of the path, if present (public member function) | |
returns the root path of the path, if present (public member function) |