std::vector<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
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Removes the last element of the container.
Calling pop_back
on an empty container is undefined.
No iterators or references except for back() and end() are invalidated.
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
(none)
Example
Run this code
#include <vector> #include <iostream> template<typename T> void print(T const & xs) { std::cout << "[ "; for(auto const & x : xs) { std::cout << x << ' '; } std::cout << "]\n"; } int main() { std::vector<int> numbers; print(numbers); numbers.push_back(5); numbers.push_back(3); numbers.push_back(4); print(numbers); numbers.pop_back(); print(numbers); }
Output:
[ ] [ 5 3 4 ] [ 5 3 ]
See also
adds an element to the end (public member function) |