std::deque<T,Allocator>::erase
(1) | ||
iterator erase( iterator pos ); |
(until C++11) | |
iterator erase( const_iterator pos ); |
(since C++11) | |
(2) | ||
iterator erase( iterator first, iterator last ); |
(until C++11) | |
iterator erase( const_iterator first, const_iterator last ); |
(since C++11) | |
Erases the specified elements from the container.
pos
.[first, last)
.All iterators and references are invalidated, unless the erased elements are at the end or the beginning of the container, in which case only the iterators and references to the erased elements are invalidated.
It is unspecified when the past-the-end iterator is invalidated. | (until C++11) |
The past-the-end iterator is also invalidated unless the erased elements are at the beginning of the container and the last element is not erased. | (since C++11) |
The iterator pos
must be valid and dereferenceable. Thus the end() iterator (which is valid, but is not dereferencable) cannot be used as a value for pos
.
The iterator first
does not need to be dereferenceable if first==last
: erasing an empty range is a no-op.
Parameters
pos | - | iterator to the element to remove |
first, last | - | range of elements to remove |
Type requirements | ||
-T must meet the requirements of MoveAssignable.
|
Return value
Iterator following the last removed element. If the iterator pos
refers to the last element, the end() iterator is returned.
Exceptions
Does not throw unless an exception is thrown by the assignment operator of T
.
Complexity
Linear: the number of calls to the destructor of T is the same as the number of elements erased, the number of calls to the assignment operator of T is no more than the lesser of the number of elements before the erased elements and the number of elements after the erased elements
Example
#include <deque> #include <iostream> int main( ) { std::deque<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()+2, c.begin()+5); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; // Erase all even numbers (C++11 and later) for (auto it = c.begin(); it != c.end(); ) { if (*it % 2 == 0) { it = c.erase(it); } else { ++it; } } for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; }
Output:
0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 6 7 8 9 1 7 9
See also
clears the contents (public member function) |