std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_weekday_last)
From cppreference.com
< cpp | chrono | year month weekday last
constexpr std::chrono::year_month_weekday_last operator+(const std::chrono::year_month_weekday_last& ymwdl, |
(since C++20) | |
constexpr std::chrono::year_month_weekday_last operator+(const std::chrono::months& dm, |
(since C++20) | |
constexpr std::chrono::year_month_weekday_last operator+(const std::chrono::year_month_weekday_last& ymwdl, |
(since C++20) | |
constexpr std::chrono::year_month_weekday_last operator+(const std::chrono::years& dy, |
(since C++20) | |
constexpr std::chrono::year_month_weekday_last operator-(const std::chrono::year_month_weekday_last& ymwdl, |
(since C++20) | |
constexpr std::chrono::year_month_weekday_last operator-(const std::chrono::year_month_weekday_last& ymwdl, |
(since C++20) | |
1-2) Adds dm.count() months to the date represented by
ymwdl
. The result has the same year()
and month()
as std::chrono::year_month(ymwdl.year(), ymwdl.month()) + dm and the same weekday()
as ymwdl
.3-4) Adds dy.count() years to the date represented by
ymwdl
. The result is equivalent to std::chrono::year_month_weekday_last(ymwdl.year() + dy, ymwdl.month(), ymwd.weekday_last()).5) Subtracts dm.count() months from the date represented by
ymwdl
. Equivalent to ymwdl+ -dm.6) Subtracts dy.count() years from the date represented by
ymwdl
. Equivalent to ymwdl + -dy.