std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day_last)
From cppreference.com
< cpp | chrono | year month day last
Defined in header <chrono>
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constexpr std::chrono::year_month_day_last operator+(const std::chrono::year_month_day_last& ymdl, const std::chrono::months& dm) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day_last operator+(const std::chrono::months& dm, const std::chrono::year_month_day_last& ymdl) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day_last operator+(const std::chrono::year_month_day_last& ymdl, const std::chrono::years& dy) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day_last operator+(const std::chrono::years& dy, const std::chrono::year_month_day_last& ymdl) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day_last operator-(const std::chrono::year_month_day_last& ymdl, const std::chrono::months& dm) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day_last operator-(const std::chrono::year_month_day_last& ymdl, const std::chrono::years& dy) noexcept; |
(since C++20) | |
1-2) Adds dm.count() months to the date represented by
ymdl
. The result has the same year()
and month()
as std::chrono::year_month(ymdl.year(), ymdl.month()) + dm.3-4) Adds dy.count() years to the date represented by
ymdl
. The result is equivalent to std::chrono::year_month_day_last(ymdl.year() + dy, ymdl.month_day_last()).5) Subtracts dm.count() months from the date represented by
ymdl
. Equivalent to ymdl + -dm.6) Subtracts dy.count() years from the date represented by
ymdl
. Equivalent to ymdl + -dy.