std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day)
From cppreference.com
< cpp | chrono | year month day
Defined in header <chrono>
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constexpr std::chrono::year_month_day operator+(const std::chrono::year_month_day& ymd, const std::chrono::months& dm) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::months& dm, const std::chrono::year_month_day& ymd) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::year_month_day& ymd, const std::chrono::years& dy) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day operator+(const std::chrono::years& dy, const std::chrono::year_month_day& ymd) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day operator-(const std::chrono::year_month_day& ymd, const std::chrono::months& dm) noexcept; |
(since C++20) | |
constexpr std::chrono::year_month_day operator-(const std::chrono::year_month_day& ymd, const std::chrono::years& dy) noexcept; |
(since C++20) | |
1-2) Adds dm.count() months to the date represented by
ymd
. The result has the same day()
as ymd
and the same year()
and month()
as std::chrono::year_month(ymd.year(), ymd.month()) + dm.3-4) Adds dy.count() years to the date represented by
ymd
. The result is equivalent to std::chrono::year_month_day(ymd.year() + dy, ymd.month(), ymd.day().5) Subtracts dm.count() months from the date represented by
ymd
. Equivalent to ymd + -dm.6) Subtracts dy.count() years from the date represented by
ymd
. Equivalent to ymd + -dy.Notes
Even if ymd.ok()
is true, the resulting year_month_day
may not represent a valid date if ymd.day() is 29, 30, or 31.