isfinite
From cppreference.com
Defined in header <math.h>
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#define isfinite(arg) /* implementation defined */ |
(since C99) | |
Determines if the given floating point number arg
has finite value i.e. it is normal, subnormal or zero, but not infinite or NaN. The macro returns an integral value.
FLT_EVAL_METHOD is ignored: even if the argument is evaluated with more range and precision than its type, it is first converted to its semantic type, and the classification is based on that.
Parameters
arg | - | floating point value |
Return value
Nonzero integral value if arg
has finite value, 0 otherwise.
Example
Run this code
#include <stdio.h> #include <math.h> #include <float.h> int main(void) { printf("isfinite(NAN) = %d\n", isfinite(NAN)); printf("isfinite(INFINITY) = %d\n", isfinite(INFINITY)); printf("isfinite(0.0) = %d\n", isfinite(0.0)); printf("isfinite(DBL_MIN/2.0) = %d\n", isfinite(DBL_MIN/2.0)); printf("isfinite(1.0) = %d\n", isfinite(1.0)); printf("isfinite(exp(800)) = %d\n", isfinite(exp(800))); }
Possible output:
isfinite(NAN) = 0 isfinite(INFINITY) = 0 isfinite(0.0) = 1 isfinite(DBL_MIN/2.0) = 1 isfinite(1.0) = 1 isfinite(exp(800)) = 0
References
- C11 standard (ISO/IEC 9899:2011):
- 7.12.3.2 The isfinite macro (p: 236)
- C99 standard (ISO/IEC 9899:1999):
- 7.12.3.2 The isfinite macro (p: 216-217)
See also
(C99) |
classifies the given floating-point value (function) |
(C99) |
checks if the given number is infinite (function) |
(C99) |
checks if the given number is NaN (function) |
(C99) |
checks if the given number is normal (function) |