_Alignof operator
From cppreference.com
Queries the alignment requirement of its operand type.
Syntax
_Alignof( type-name )
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(since C11) | ||||||||
This operator is typically used through the convenience macro alignof, which is provided in the header stdalign.h
Explanation
Returns the alignment requirement of the type named by type-name. If type-name is an array type, the result is the alignment requirement of the array element type. The type-name cannot be function type or an incomplete type.
The result is an integer constant of type size_t.
The operand is not evaluated (so external identifiers used in the operand do not have to be defined)
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If type is a VLA type, its size expression is not evaluated. |
(since C2x) |
Notes
The use of alignof with expressions is allowed by some C compilers as a non-standard extension.
Keywords
Example
Run this code
#include <stdio.h> #include <stddef.h> #include <stdalign.h> int main(void) { printf("Alignment of char = %zu\n", alignof(char)); printf("Alignment of max_align_t = %zu\n", alignof(max_align_t)); printf("alignof(float[10]) = %zu\n", alignof(float[10])); printf("alignof(struct{char c; int n;}) = %zu\n", alignof(struct {char c; int n;})); }
Possible output:
Alignment of char = 1
Alignment of max_align_t = 16
alignof(float[10]) = 4
alignof(struct{char c; int n;}) = 4References
- C11 standard (ISO/IEC 9899:2011):
- 6.5.3.4 The sizeof and _Alignof operators (p: 90-91)
See also
| (C11) |
a type with alignment requirement as great as any other scalar type (typedef) |
| _Alignas specifier | sets alignment requirements of an object (since C11) |