std::wmemcpy
From cppreference.com
Defined in header <cwchar>
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wchar_t* wmemcpy( wchar_t* dest, const wchar_t* src, std::size_t count ); |
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Copies exactly count
successive wide characters from the wide character array pointed to by src
to the wide character array pointed to by dest
. If the objects overlap, the behavior is undefined. If count
is zero, the function does nothing.
Parameters
dest | - | pointer to the wide character array to copy to |
src | - | pointer to the wide character array to copy from |
count | - | number of wide characters to copy |
Return value
dest
Notes
This function's analog for byte strings is std::strncpy, not std::strcpy.
This function is not locale-sensitive and pays no attention to the values of the wchar_t objects it copies: nulls as well as invalid characters are copied too.
Example
Run this code
#include <iostream> #include <cwchar> #include <clocale> #include <locale> int main(void) { wchar_t from1[] = L"नमस्ते"; const size_t sz1 = sizeof from1 / sizeof *from1; wchar_t from2[] = L"Բարև"; const size_t sz2 = sizeof from2 / sizeof *from2; wchar_t to[sz1 + sz2]; std::wmemcpy(to, from1, sz1); // copy from1, along with its null terminator std::wmemcpy(to + sz1, from2, sz2); // append from2, along with its null terminator std::setlocale(LC_ALL, "en_US.utf8"); std::cout.imbue(std::locale("en_US.utf8")); std::wcout << "Wide array contains: "; for(size_t n = 0; n < sizeof to / sizeof *to; ++n) if(to[n]) std::wcout << to[n]; else std::wcout << "\\0"; std::wcout << '\n'; }
Possible output:
Wide array contains: नमस्ते\0Բարև\0
See also
copies a certain amount of characters from one string to another (function) | |
copies a certain amount of wide characters between two, possibly overlapping, arrays (function) | |
C documentation for wmemcpy
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