std::enable_shared_from_this::operator=
From cppreference.com
< cpp | memory | enable shared from this
enable_shared_from_this<T>& operator=( const enable_shared_from_this<T> &obj ); |
(since C++11) | |
Does nothing; returns *this.
Parameters
obj | - | an enable_shared_from_this to assign to *this
|
Return value
*this
Exceptions
noexcept specification:
noexcept
Notes
The private std::weak_ptr<T> member is not affected by this assignment operator.
Example
Note: enable_shared_from_this::operator= is defined as protected
in order to prevent accidental slicing but allow derived classes to have default assignment operators.
Run this code
#include <memory> #include <iostream> class SharedInt : public std::enable_shared_from_this<SharedInt> { public: explicit SharedInt(int n) : mNumber(n) {} SharedInt(const SharedInt&) = default; SharedInt(SharedInt&&) = default; ~SharedInt() = default; // Both assignment operators use enable_shared_from_this::operator= SharedInt& operator=(const SharedInt&) = default; SharedInt& operator=(SharedInt&&) = default; int number() const { return mNumber; } private: int mNumber; }; int main() { std::shared_ptr<SharedInt> a = std::make_shared<SharedInt>(2); std::shared_ptr<SharedInt> b = std::make_shared<SharedInt>(4); *a = *b; std::cout << a->number() << std::endl; }
Output:
4
See also
(C++11) |
smart pointer with shared object ownership semantics (class template) |